Kieran AllenCourse Number: CHM1045Date: 9th July 2024Lewis Structure of IF3:To draw the Lewis structure of IF3:Count the total valence electrons:Iodine (I) has 7 valence electrons.Fluorine (F) has 7 valence electrons each, multiplied by 3 gives 21 electrons.Total valence electrons = 7 (I) + 21 (3F) = 28 electrons.Determine the central atom:Iodine (I) is less electronegative than fluorine (F), so Iodine will be the central atom.Connect atoms with single bonds:Iodine (I) will form single bonds with each Fluorine atom (F).Place remaining electrons:Distribute the remaining electrons as lone pairs on the fluorine atoms to satisfy the octet rule.Check for octet rule:Each fluorine (F) atom should have 8 electrons (2 from the bond and 6 as lone pairs).Iodine (I) will have electrons around it to complete its octet.Formal Charges Calculation:Formal charge (FCFCFC) is calculated using the formula:FC=Valence electrons−Owned electronsFC = \text{Valence electrons} - \text{Owned electrons}FC=Valence electrons−Owned electronsWhere:Valence electrons = Number of valence electrons in the free atom.Owned electrons = Number of lone pair electrons + 0.5 * Number of bonding electrons.Let's calculate the formal charges for each atom in IF3.Iodine (I):Valence electrons of Iodine = 7Lone pair electrons = 0Bonding electrons (3 bonds) = 6Formal charge FC=7−(0+6)=1FC = 7 - (0 +