Dba 8475 Unit Iii Case Study

Brandon PedrazaColumbia Southern UniversityDBA 8475Unit III Case Study#1 What is the daily capacity of the assembly line designed by the engineers?Daily Operation Time = 7.5 hoursTask #63 is a parallel task that requires essentially no labor thus the time for station 9 is 102 sec. With this being said, station 2 becomes the bottleneck with a time of 114 sec. Capacity = Operating Time/Production Time per Unit = (7.5*60*60)/114 = 236 units per day#2 When it is running at maximum capacity, what is the efficiency of the line?Efficiency = Total Task Time/ (Number of stations * Cycle time) = 1050/(10*114) = 92.1%Therefore when running at maximum capacity the efficiency of the production line is only 92.1%#3 How should the line be redesigned to operate at the target 300 units per day, assuming that no overtime will be used? What is the efficiency of your new design?300 units * 114 sec/(60*60) = 9.5 hoursIn order to produce 300 units per day the factory would have to run 9.5 hours per day. Therefore the cycle time will need