Math 110 Module 3 Exam Questions And Answers- Portage Learning

Stat st cs - Por tage O n l i n e Su m m e r / MATH 110 Module 3 Exam Questions and Answers- PortageLearningModule 3 ExamExam Page 1Suppose A and B are two events with probabilities:P(A c )=.40,P(B)=.45,P(A B)=.60.Find the following:a) P(AB).p(anb) = p(a) + p(b) - p(aub) p(a) = 1 - p(a^c)p(a^c) = 0.401 - 0.40 = 0.60p(a) = 0.600.60 + 0.45 - 0.60 = 0.45P(AnB) = 0.45b) P(A).p(a) = 1 - p(a^c) p(a^c)= 0.401 - 0.40 = 0.60P(A) = 0.60c) P(B c).p(b) = 1 - p(b^c)Stat st cs - Por tage O n l i n e Su m m e r / rearranged to find p(b^c) = 1 - p(b)1 - 0.45 = 0.55P(B^c) = 0.55Answer KeySuppose A and B are two events with probabilities:P(A c )=.40,P(B)=.45,P(A B)=.60.Find the following:a) P(AB).For P(AB). Use P(A B)=P(A)+P(B)-P(AB) and rearrange toP(AB)=P(A)+P(B)-P(A B). But for this equation, we need P(A) which we can find by using P(A)=1- P(A^c ). So, P(A)=1-.40= .60.P(AB)=.60+.45-.60=.45.b) P(A).P(A) was found above as .60.c) P(B c).For P(B c ). Use P(B)=1-P(B c ) which may be rearranged to (B c )=1-P(B).P(B c )=1-.45=.55.Exam Page 2Suppose you are going to make a password that consists