The line shown on the graph is y = 3x + 10y = 3x + 10 . Use the point-slope form of a line, y − y1 = m(x−x1) . Two points on the line are (−2,4) and (−4,−2). Using the slope formula, you find the slope m. m = y2 − y1/ x2 − x1 = −2 − 4/−4 − (−2) = 3 Substitute this and the coordinates of the first point into the point-slope equation of a line, and solve for y. y − 4 = 3(x−(−2)) y − 4 = 3x + 6 y = 3x + 10 {Ans: What is the equation of the line? A. y = 3x + 10 B. y = −1/3x − 10 C. y = 3x − 10 D. y = 1/3x + 10}The formula for the area of a trapezoid is: A = 1/2h (b1+b2) Substitute given values into the formula and solve for the unknown base: 864 = 1/2 ⋅ 24 (30+b2) 864 = 12 (30+b2) 864 = 360 + 12b2 504 = 12b2 42 = b2 The length of the base is 42 cm. {Ans: The area of a trapezoid is 864 cm^2. It has a