What is the sum of the solutions of the following equation? 0= −3x2 + 3x + 126 A) −13 B) −1 C) 1 D) 13 {Ans: C To find the sum of the solutions, first find the solutions. Begin by simplifying the quadratic by factoring out the greatest common factor. 0 = −3x^2 + 3x + 126 (divide all by -3) 0= x^2 - x - 42 (switch to subtraction to factor out the negative) Factoring method. 6 * 7= 42 The solutions of this quadratic are −6an d 7; their sum is 1.}∠1 and ∠2 are supplementary angles, and ∠2 and ∠3 are complementary angles. Given that ∠3 and ∠4 are vertical angles and ∠4 Is 40°, what is the measure of ∠1? A) 40° B) 50° C) 130° D) 140° {Ans: C supplementary angles' measures add up to 180°, complementary angles' measures add up to 90°, and vertical angles have the same measures. m∠4 = 40° ° and it is vertical angles with ∠3, then m∠3 = 40° m∠2 + m∠3 = 90° m∠2 + 40° = 90° ∠2 = 90°